<p align="right">Last Update: <font color="#4f81bd">December 11, 2024</font></p>
Determine the range without using values.
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![[86E00BA8-1EAA-4DDB-9BE1-29EFECA14F75.jpeg]]
### Horizontal
$\Delta x$ = range
$\vec{v}_x$ = horizontal velocity
$t$ = flight time
Formula for range
$\Delta{\vec {x}} = \vec{v}{_x} \cdot t$
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Find $t_{\frac{1}{2}}$ (time to peek)
$\vec{v}{_{1y}} = \vec{v}_{0y} + \vec{a}t_\frac{1}{2}$
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Rearrange for $t_{\frac{1}{2}}$
$t_{\frac{1}{2}} = \frac{\vec{v}_{1y}-\vec{v}_{0y}}{a}$
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Substitute in values
$t_{\frac{1}{2}} = \frac{0-\vec{v}\cdot sin\theta}{-g}$
$t_{\frac{1}{2}} = \frac{\vec{v}\cdot sin\theta}{g}$
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Double time to get to time of flight
$t = \frac{2\cdot\vec{v}\cdot sin\theta}{g}$
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Substitute time of flight found above into formula for range
$\Delta{\vec {x}} = \vec{v_x} \cdot \frac{2\cdot\vec{v}\cdot sin\theta}{g}$
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Substitute $\vec{v_x}$ with $\vec{v}\cdot\cos\theta$
$\Delta{\vec {x}} = \vec{v}\cdot\cos\theta \cdot \frac{2\cdot\vec{v}\cdot sin\theta}{g}$
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Algebraically combine values
$\Delta{\vec {x}} = \frac{\vec{v} {^2}\cdot sin 2\theta}{g}$
## Video
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### Related Topics
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Return [[Home|Home]] | [[Notes Vault/Physics Notes Vault/Kinematics/2D Motion/Projectiles|Projectiles]] | [[Time of Flight]] | [[Find Max Height|Maximum Height]] | [[Find Range|Range]]